ALTERNATIVE WAY TO CALCULATE DELIVERY DATE
In this method, the calculation is a bit difficult but all the same if you put your effort you will learn it.
Lets assume Mrs Sparkwell saw her last menstruation in month of May, precisely 22 May 2005 and it lasted for 4 days e.g 22,23,24,25(started on 22,the first day) Assume there are 30 days in a month.
The calculation will look like this:
MAY
1 2 3 4 5 6 7 8 9 10
11 12 13 14 15 16 17
18 19 20 21 "22" 23
24 25 26 27 28 29 30
1)Add 10 days to the first day of the last period (it will bring the date into another month entirely)
22 /05 /2005
+10 (adding 10 + 22= 32 which takes you to 2nd JUNE). Now we have new date 2 /06/ 2005)
2)Subtract 3 months from the month: 2 /06 /2005
-3 (after subtracting we will have 2 /03 /2005)
3)Add one year: ( after adding one year, you will have 2 /03 /2006
MRS SPARKWELL WILL BE DUE FOR DELIVERY ON 2ND MARCH 2006.
Lets assume Mrs Sparkwell saw her last menstruation in month of May, precisely 22 May 2005 and it lasted for 4 days e.g 22,23,24,25(started on 22,the first day) Assume there are 30 days in a month.
The calculation will look like this:
MAY
1 2 3 4 5 6 7 8 9 10
11 12 13 14 15 16 17
18 19 20 21 "22" 23
24 25 26 27 28 29 30
1)Add 10 days to the first day of the last period (it will bring the date into another month entirely)
22 /05 /2005
+10 (adding 10 + 22= 32 which takes you to 2nd JUNE). Now we have new date 2 /06/ 2005)
2)Subtract 3 months from the month: 2 /06 /2005
-3 (after subtracting we will have 2 /03 /2005)
3)Add one year: ( after adding one year, you will have 2 /03 /2006
MRS SPARKWELL WILL BE DUE FOR DELIVERY ON 2ND MARCH 2006.